A) spontaneous mutation.
B) antigenic variation.
C) quorum sensing.
D) vertical gene transfer.
E) indirect selection.
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Multiple Choice
A) antibiotic resistance.
B) virulence factors.
C) mutation.
D) sigma factors.
E) mutant.
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Multiple Choice
A) The patient has become resistant to penicillin and he needs to take a different medication.
B) The bacteria causing the infection are resistant to penicillin; a different antibiotic is needed.
C) Bacteria are never killed by a single type of antibiotic; combinations of drugs are needed.
D) Penicillin has been overused by people and it no longer works against any bacteria; it can be used against viruses.
E) The patient's body is neutralizing the antibiotic; he needs to take a probiotic to help the penicillin work.
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Multiple Choice
A) The colony that is missing from plate B is an auxotroph that cannot synthesize histidine.
B) The prototrophs are resistant to penicillin but the auxotrophs are sensitive to this antibiotic.
C) Prototrophs and auxotrophs in this experiment are resistant to penicillin.
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Multiple Choice
A) an F plasmid.
B) a Y chromosome.
C) diploid chromosomes.
D) an SOS response.
E) an F plasmid AND diploid chromosomes.
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Multiple Choice
A) It is a point mutation-a single base pair is altered, causing the change of one amino acid in the protein that changes the function of that protein.
B) It is a point mutation-a single base pair is altered, causing the change of one amino acid in the protein that stops the correct formation of a protein.
C) It is a point mutation-a single base pair is altered, causing the change of one amino acid in the protein that does not affect the function of that protein.
D) It is a frameshift mutation-base pairs are added or deleted, causing the change of one or more amino acids in the protein but does not affect the function of that protein.
E) It is a point mutation-several base pairs are altered, causing the change of many amino acids in the protein that completely changes the function of that protein.
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Multiple Choice
A) preventing DNA replication.
B) inhibiting transcription.
C) stopping capsule formation.
D) inhibiting protein synthesis.
E) preventing protein packaging.
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Multiple Choice
A) conjugation AND transformation.
B) conjugation AND transposons.
C) transformation AND transduction.
D) transduction AND transposons.
E) transformation AND transposons.
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Multiple Choice
A) four nucleotides to covalently bind together.
B) thymine dimers.
C) adenine complementary base pairing with cytosine.
D) the addition of uracil.
E) cytosine trimers.
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Multiple Choice
A) gas chromatography.
B) replica plating.
C) direct selection.
D) reversion.
E) intercalation.
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Multiple Choice
A) base analogs.
B) intercalating agents.
C) transposons.
D) inverted repeats.
E) mutagens.
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Multiple Choice
A) Fleming.
B) Lederberg.
C) Ames.
D) Crick.
E) McClintock.
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Multiple Choice
A) the genotype of bacteria that lack a functional gene for histidine synthesis AND bacteria that are auxotrophic for histidine.
B) the genotype of bacteria that have a functional gene for histidine synthesis AND bacteria that require addition of histidine to the growth medium.
C) the genotype of bacteria that have a functional gene for histidine synthesis AND bacteria that are auxotrophic for histidine.
D) the genotype of bacteria that lack a functional gene for histidine synthesis AND bacteria that have a hers gene.
E) the genotype of bacteria that lack a functional gene for histidine synthesis AND bacteria that do not require addition of histidine to the growth medium.
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Multiple Choice
A) No. There's always one specific antibiotic that will be the most effective, and that is the only antibiotic that should be used to treat a particular infection.
B) Yes. As long as the length of time is the same, the two treatments should be essentially the same in terms of effectively eliminating the infection.
C) No. Taken sequentially, the first antibiotic will select for the small portion of the population that will spontaneously mutate toward resistance. Then, the second antibiotic will do the exact same thing-selecting for resistance to the second drug from the few bacterial cells that remained from the first drug treatment.
D) It depends. Provided that the majority of the infectious agent is killed off by the first drug, the likelihood that the few that are left would not also be killed by the second drug is low. However, simultaneous treatment should be more effective at eliminating all the microbes in the shortest time possible, and with the least probability of selection for multiple drug resistance mutations.
E) Yes. Each antibiotic will kill all the cells that are sensitive to it, no matter if the drugs are taken simultaneously or sequentially. The important thing is to take the medication for as few days as possible.
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Multiple Choice
A) phase variation.
B) antigenic sensing.
C) two-component control.
D) transduction.
E) gene splicing.
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True/False
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Multiple Choice
A) The bacteria in the colonies are His−, Val−, Trp+, Leu+.
B) The bacteria in the colonies are His−, Val+, Trp+, Leu+.
C) The bacteria in the colonies are His−, Val−, Trp−, Leu−.
D) The bacteria in the colonies are His+, Val+, Trp+, Leu+.
E) The bacteria in the colonies are His+, Val+, Trp+, Leu+, PenR.
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Multiple Choice
A) the sex pilus.
B) recipient cell DNA replication.
C) antibiotic resistance.
D) the Y chromosome.
E) bacterial flagella.
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True/False
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Multiple Choice
A) They may simply have a higher proportion of T nucleotides next to each other in their DNA sequences than other bacteria, leading to more possible dimers being formed.
B) They may simply have a higher proportion of T nucleotides next to each other in their DNA sequences than other bacteria, leading to more possible dimers being formed AND they may have a stronger expression of photoreactivation enzymes, leading to formation of more thymine dimers.
C) They may simply have a higher proportion of T nucleotides next to each other in their DNA than other bacteria, leading to more possible dimers being formed AND they may have a weaker expression of photoreactivation enzymes, leading to formation of more thymine dimers.
D) They may have a stronger expression of photoreactivation enzymes, leading to more thymine dimers being formed and retained.
E) They may have a weaker expression of photoreactivation enzymes, leading to more thymine dimers being formed and retained.
Correct Answer
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