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Express the confidence interval using the indicated format. -Express the confidence interval 0.62<p<0.720.62 < p < 0.72 in the form of p^±E\hat { p } \pm E .


A) 0.67±0.050.67 \pm 0.05
B) 0.62±0.10.62 \pm 0.1
C) 0.62±0.050.62 \pm 0.05
D) 0.67±0.10.67 \pm 0.1

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Hannah selected a simple random sample of all adults in her town and, based on this sample, constructed a confidence interval for the mean salary of all adults in the town. However, the distribution of salaries in the town is not exactly normal. Will the confidence interval still give a good estimate of the mean salary?

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Yes, confidence interval procedures are ...

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The following confidence interval is obtained for a population proportion, p:(0.734,0.778) p : ( 0.734,0.778 ) Use these confidence interval limits to find the margin of error, E.


A) 0.020
B) 0.044
C) 0.022
D) 0.023

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Describe the process for finding the confidence interval for a population proportion.

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1) Find the summary statistics \(\hat { \mathrm { p } }\) and \(\hat { \mathrm { q } }\) 2) Compute E using the z distribution and the formula \(E = { } _ { z } \alpha / 2 \cdot \sqrt { \frac { \hat { p q } } { \mathrm { n } } } .\) 3) Find the interval by adding \(E\) to \(\hat { p }\) and then subtracting \(E\) from \(\hat { p }\). 4) Interpret the interval.

Do one of the following, as appropriate: (a) Find the critical value z?/2, (b) find the critical value t?/2, (c) state that neither the normal nor the t distribution applies. - 91%;n=45;σ91 \% ; \mathrm { n } = 45 ; \sigma is known; population appears to be very skewed.


A) zα/2=1.75\mathrm { z } _ { \alpha / 2 } = 1.75
B) tα/2=1.34\mathrm { t } _ { \alpha / 2 } = 1.34
C) zα/2=1.70\mathrm { z } _ { \alpha / 2 } = 1.70
D) tα/2=1.645t _ { \alpha / 2 } = 1.645

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Express the confidence interval using the indicated format. -Express the confidence interval (0.326,0.458) ( 0.326,0.458 ) in the form of p^±E\hat { p } \pm \mathrm { E } .


A) 0.392±0.0660.392 \pm 0.066
B) 0.326±0.1320.326 \pm 0.132
C) 0.392±0.1320.392 \pm 0.132
D) 0.326±0.0660.326 \pm 0.066

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A one-sided confidence interval for p\mathrm { p } can be written as p<p^+E\mathrm { p } < \hat { \mathrm { p } } + \mathrm { E } or p>p^E\mathrm { p } > \hat { \mathrm { p } } - \mathrm { E } where the margin of error E\mathrm { E } is modified by replacing zα/2\mathrm { z } \alpha / 2 with zα\mathrm { z } _ { \alpha } . If a teacher wants to report that the fail rate on a test is at most xx with 90%90 \% confidence, construct the appropriate one-sided confidence interval. Assume that a simple random sample of 52 students results in 7 who fail the test.


A) p<0.074p < 0.074
B) p<0.212\mathrm { p } < 0.212
C) p <0.195< 0.195
D) p>0.074p > 0.074

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Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the given statistics and confidence level. Round the margin of error to four decimal places. -98% confidence; the sample size is 810, of which 20% are successes


A) 0.0275
B) 0.0288
C) 0.0327
D) 0.0362

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Why would manufacturers and businesses be interested in constructing a confidence interval for the population variance? Would manufacturers and businesses want large or small variances?

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Manufacturers and businesses would be in...

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Express the confidence interval using the indicated format. -Express the confidence interval 0.061<p<0.579- 0.061 < \mathrm { p } < 0.579 in the form of p^±E\hat { \mathrm { p } } \pm \mathrm { E } .


A) 0.259±0.320.259 \pm 0.32
B) 0.2590.320.259 - 0.32
C) 0.259±0.50.259 \pm 0.5
D) 0.32±0.50.32 \pm 0.5

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A

To be able to say with 95% confidence level that the standard deviation of a data set is within 10% of the population's standard deviation, the number of observations within the data set must be greater than or equal to what quantity?


A) 805
B) 335
C) 250
D) 192

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Use the confidence level and sample data to find a confidence interval for estimating the population µ. Round your answer to the same number of decimal places as the sample mean. -A laboratory tested 73 chicken eggs and found that the mean amount of cholesterol was 230 milligrams with σ=17.4\sigma = 17.4 milligrams. Construct a 95%95 \% confidence interval for the true mean cholesterol content, μ\mu , of all such eggs.


A) 225mg<μ<234mg225 \mathrm { mg } < \mu < 234 \mathrm { mg }
B) 225mg<μ<233mg225 \mathrm { mg } < \mu < 233 \mathrm { mg }
C) 226mg<μ<234mg226 \mathrm { mg } < \mu < 234 \mathrm { mg }
D) 227mg<μ<235mg227 \mathrm { mg } < \mu < 235 \mathrm { mg }

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Use the given data to find the minimum sample size required to estimate the population proportion. -Margin of error: 0.044; confidence level: 95%; p^\hat{p} and q^\hat{q} unknown


A) 635
B) 497
C) 352
D) 405

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Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation σ. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation. -To find the standard deviation of the diameter of wooden dowels, the manufacturer measures 19 randomly selected dowels and finds the standard deviation of the sample to be s=0.16s = 0.16 . Find the 95\% confidence interval for the population standard deviation σ\sigma .


A) 0.13<σ<0.220.13 < \sigma < 0.22
B) 0.11<σ<0.250.11 < \sigma < 0.25
C) 0.15<σ<0.210.15 < \sigma < 0.21
D) 0.12<σ<0.240.12 < \sigma < 0.24

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Find the critical value xL2x _ { L } ^ { 2 } corresponding to a sample size of 4 and a confidence level of 95 percent.


A) 7.815
B) 9.348
C) 0.216
D) 0.352

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Under what three conditions is it appropriate to use the t distribution in place of the standard normal distribution?

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1) \(\mathrm { n } \leq 30\) 2) \(\sigma\) is unknown, and 3) the parent population is essentially normal

A paper published the results of a poll. It stated that, based on a sample of 1000 married men, 51% of married men say that they would marry the same woman again. The margin of error was given as ±3 percentage points and the confidence level was given as 95%. What does it mean that the margin of error was ±3 percentage points?

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If 51% is used as an estimate of the per...

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Draw a diagram of the chi-square distribution. Discuss its shape and values.

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The following graph illustrates examples...

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n=51,x=23;95%\mathrm { n } = 51 , \mathrm { x } = 23 ; 95 \% confidence


A) 0.336<p<0.5660.336 < p < 0.566
B) 0.313<p<0.5890.313 < p < 0.589
C) 0.335<p<0.5670.335 < p < 0.567
D) 0.314<p<0.5880.314 < p < 0.588

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Find the critical value χR2\chi { } _ { \mathrm { R } } ^ { 2 } corresponding to a sample size of 19 and a confidence level of 99 percent.


A) 34.80534.805
B) 37.15637.156
C) 6.2656.265
D) 7.0157.015

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