Correct Answer
verified
True/False
Correct Answer
verified
Short Answer
Correct Answer
verified
Multiple Choice
A) inequality join
B) outer join
C) equality join
D) all of the above
Correct Answer
verified
True/False
Correct Answer
verified
Short Answer
Correct Answer
verified
True/False
Correct Answer
verified
Short Answer
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
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Multiple Choice
A) common column
B) equiv-column
C) inner columns
D) simple columns
Correct Answer
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Multiple Choice
A) SELECT lastname, firstname, order#
FROM customers NATURAL JOIN orders;
B) SELECT lastname, firstname, order#
FROM customers c LEFT OUTER JOIN orders o
ON
C) SELECT lastname, firstname, order#
FROM customers RIGHT OUTER JOIN orders;
D) customer# = o.customer#;
E) SELECT lastname, firstname, order#
FROM customers JOIN orders USING (customer#) ;
Correct Answer
verified
True/False
Correct Answer
verified
True/False
Correct Answer
verified
Multiple Choice
A) OUTER JOIN
B) CROSS JOIN
C) NATURAL JOIN
D) JOIN...USING
Correct Answer
verified
True/False
Correct Answer
verified
Short Answer
Correct Answer
verified
Multiple Choice
A) FROM o orders, c customers
B) FROM o.orders,
C) FROM orders o, customers c
D) customers
E) FROM orders.o, customers.c
Correct Answer
verified
Multiple Choice
A) SELECT title
FROM customers NATURAL JOIN orders
NATURAL JOIN orderitems NATURAL JOIN books
WHERE orderdate - pubdate >= 3;
B) SELECT title,
FROM orders o, orderitems oi, books b
WHERE
C) isbn = oi.isbn AND oi.order# = o.order# AND (orderdate-pubdate) /365 >= 3;.
D) isbn = oi.isbn AND oi.order# = o.order# AND orderdate - pubdate >= 3;,
E) SELECT title.
FROM orders o, orderitems oi, books b
WHERE..
Correct Answer
verified
Short Answer
Correct Answer
verified
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