Question 1

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Accepted Answer

A)   -158°C
B)   9.6°C
C)   65°C
D)   500°C

Question 2

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Accepted Answer

A)   1.1 atm
B)   0.80 atm
C)   0.54 atm
D)   0.40 atm
E)   1.3 atm

Question 3

Convert 1.50 atm to mm Hg.

Accepted Answer

A)   760 mm Hg
B)   875 mm Hg
C)   1140 mm Hg
D)   1000 mm Hg
E)   1520 mm Hg

Question 4

How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.60 atm) according to the following reaction? Assume that there is excess Xe.
Xe(g) + 3 F2(g) → XeF6(g)

Accepted Answer

A)   1.21 × 1023 molecules XeF6
B)   8.25 × 1023 molecules XeF6
C)   2.75 × 1023 molecules XeF6
D)   7.29 × 1023 molecules XeF6
E)   1.37 × 1023 molecules XeF6

Question 5

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

Accepted Answer

A)   64.0 K
B)   -209 K
C)   337 K
D)   28.0 K

Exam 11: Gases

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Correct Answer
verified

Convert 1.50 atm to mm Hg.

Correct Answer
verified

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Correct Answer
verified

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

Correct Answer
verified

How many molecules of XeF₆are formed from 12.9 L of F₂ (at 298 K and 2.60 atm) according to the following reaction? Assume that there is excess Xe. Xe(g) + 3 F₂(g) → XeF₆(g)

Correct Answer
verified

Exam 11: Gases

A mixture of 10.0 g of Ne and 10.0 g Ar have a total pressure of 1.6 atm.What is the partial pressure of Ne?

Correct AnswerverifiedShow Answer

Convert 1.50 atm to mm Hg.

Correct AnswerverifiedShow Answer

The volume of 350.mL of gas at 25°C is decreased to 135 mL at constant pressure.What is the final temperature of the gas?

Correct AnswerverifiedShow Answer

Calculate the temperature,in K,of 2.20 moles of gas occupying 3.30 L at 3.50 atm.

Correct AnswerverifiedShow Answer

How many molecules of XeF6 are formed from 12.9 L of F2 (at 298 K and 2.60 atm) according to the following reaction? Assume that there is excess Xe. Xe(g) + 3 F2(g) → XeF6(g)

Correct AnswerverifiedShow Answer

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

Correct Answer
verified

How many molecules of XeF₆are formed from 12.9 L of F₂ (at 298 K and 2.60 atm) according to the following reaction? Assume that there is excess Xe. Xe(g) + 3 F₂(g) → XeF₆(g)

Correct Answer
verified