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In a reaction mixture containing only reactants,what is the value of Q?


A) -1
B) 1
C) ∞
D) 0
E) It cannot be determined without concentrations.

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Consider the following reaction at equilibrium.What effect will reducing the pressure of the reaction mixture have on the system? Xe(g) + 2 F2(g) → XeF4(g)


A) The reaction will shift to the left in the direction of reactants.
B) The equilibrium constant will increase.
C) No effect will be observed.
D) The reaction will shift to the right in the direction of products.
E) The equilibrium constant will decrease.

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Determine the value of Kp for the following reaction if the equilibrium concentrations are as follows: P(NOCl) eq = 0.22 atm,P(NO) eq = 0.10 atm,P(Cl2) eq = 0.20 atm. 2 NOCl(g) ⇌ 2 NO(g) + Cl2(g)


A) 1.0
B) 24
C) 4.1 × 102
D) 4.1 × 10-2
E) 0.97

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What is △n for the following equation in relating Kc to Kp? P4(s) + 5 O2(g) ⇌ P4O10(s)


A) 3
B) 0
C) -3
D) -6
E) -5

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Determine the value of Kc for the following reaction if the equilibrium concentrations are as follows: [C3H8]= 0.15 M,[O2] = 0.35 M,[CO2] = 1.3 M,[H2O] = 2.8 M C3H8(g) + 5 O2(g) ⇌ 3 CO2(g) + 4 H2O(g)


A) 1.7 × 105
B) 3.2 × 10-6
C) 6.7 × 103
D) 7.4 × 102
E) 6.1.9 × 10-4

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Consider the following reaction at equilibrium.What effect will reducing the volume of the reaction mixture have on the system? Xe(g) + 2 F2(g) → XeF4(g)


A) The reaction will shift to the left in the direction of reactants.
B) The equilibrium constant will increase.
C) No effect will be observed.
D) The reaction will shift to the right in the direction of products.
E) The equilibrium constant will decrease.

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The reaction below has a Kc value of 3.64 × 10-3.What is the value of Kp for this reaction at 25°C? 2 NaN3(s) ⇌ 2 Na(s) + 3 N2(g)


A) 131
B) 0.613
C) 8.90 × 10-2
D) 29.9
E) 53.2

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Consider the following reaction at equilibrium.What effect will raising the pressure of the system from 5 atm to 8 atm? 2 NH3(g) ⇌ N2(g) + 3 H2(g)


A) It will shift to the right
B) It will shift to the left
C) It will have no effect
D) It will speed up the reaction
E) It will slow down the reaction

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Give the direction of the reaction,if K ≈ 1.


A) The forward reaction is favored.
B) The reverse reaction is favored.
C) Neither direction is favored.
D) If the temperature is raised, then the forward reaction is favored.
E) If the temperature is raised, then the reverse reaction is favored.

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The reaction below has a Kp value of 3.3 × 10-5.What is the value of Kc for this reaction at 700 K? 2 SO3(g) ⇌ 2 SO2(g) + O2(g)


A) 5.7 × 10-7
B) 1.7 × 106
C) 3.3 × 10-5
D) 3.0 × 104
E) 1.9 × 10-3

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For the following reaction of N2O4,the equilibrium constant is 0.593 at a particular temperature. N2O4(g) ⇌ 2 NO2(g) If the initial concentration of N2O4 is 0.880M,what are the equilibrium concentrations?


A) [N2O4] = 0.705M, [NO2] = 0.350M
B) [N2O4] = 0.678M, [NO2] = 0.404M
C) [N2O4] = 0.332M, [NO2] = 1.094M
D) [N2O4] = 0.586M, [NO2] = 0.588M
E) [N2O4] = 0.000M, [NO2] = 1.760M

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Consider the following reaction at equilibrium.What effect will reducing the pressure have on the system? C3H8(g) + 5 O2(g) ⇌ 3 CO2(g) + 4 H2O(l) ΔH° = -2220 kJ


A) The reaction will shift to the right in the direction of products.
B) The reaction will shift to the left in the direction of reactants.
C) The equilibrium constant will increase.
D) The equilibrium constant will decrease.
E) No effect will be observed.

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In which of the following reactions will Kc = Kp?


A) 4 NH3(g) + 3 O2(g) ⇌ 2 N2(g) + 6 H2O(g)
B) SO3(g) + NO(g) ⇌ SO2(g) + NO2(g)
C) 2 N2(g) + O2(g) ⇌ 2 N2O(g)
D) 2 SO2(g) + O2(g) ⇌ 2 SO3(g)
E) None of the above reactions have Kc = Kp.

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Why aren't solids or liquids included in an equilibrium expression?

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The equilibrium constant relates differe...

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Consider the following reaction at equilibrium.What effect will adding more SO3 have on the system? SO2(g) + NO2(g) ⇌ SO3(g) + NO(g)


A) The reaction will shift in the direction of products.
B) The reaction will shift to decrease the pressure.
C) No change will occur since SO3 is not included in the equilibrium expression.
D) The reaction will shift in the direction of reactants.
E) The equilibrium constant will decrease.

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Consider the following reaction: Xe(g) + 2 F2(g) → XeF4(g) A reaction mixture initially contains 2.24 atm Xe and 4.27 atm F2.If the equilibrium pressure of Xe is 0.34 atm,find the equilibrium constant (Kp) for the reaction.


A) 25
B) 0.12
C) 0.99
D) 8.3
E) 0.040

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In which of the following reactions will Kc = Kp?


A) H2(g) + I2(g) ⇌ 2 HI(g)
B) CH4(g) + H2O(g) ⇌ CO(g) + 3 H2(g)
C) N2O4(g) ⇌ 2NO2(g)
D) CO(g) + 2 H2(g) ⇌ CH3OH(g)
E) N2(g) + 3 Cl2(g) ⇌ 2 NCl3(g)

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The reaction below has a Kc value of 1.0 × 1012.What is the value of Kp for this reaction at 200 K? 2 SO2(g) + O2(g) ⇌ 2 SO3(g)


A) 6.1 × 10-14
B) 1.0 × 1012
C) 1.6 × 10-11
D) 1.6 × 1013
E) 6.1 × 1010

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The equilibrium constant is given for one of the reactions below.Determine the value of the missing equilibrium constant. 2 SO2(g) + O2(g) ⇌ 2 SO3(g) Kc = 1.7 × 106 SO3(g) ⇌ 1/2 O2(g) + SO2(g) Kc = ?


A) 3.4 × 102
B) 8.5
C) 1.3 × 103
D) 1.2 × 10-6
E) 7.7 × 10-4

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How is the reaction quotient different from an equilibrium constant for a given reaction?

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The expression for both are identical.Ho...

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