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In which one of the following solutions will acetic acid have the greatest percent ionization?


A) 0.1 M CH3COOH
B) 0.1 M CH3COOH dissolved in 1.0 M HCl
C) 0.1 M CH3COOH plus 0.1 M CH3COONa
D) 0.1 M CH3COOH plus 0.2 M CH3COONa

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A titration of an acid and base to the equivalence point results in a noticeably acidic solution.It is likely this titration involves


A) a strong acid and a weak base.
B) a weak acid and a strong base.
C) a weak acid and a weak base (where Ka equals Kb) .
D) a strong acid and a strong base.

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Calculate the pH of a buffer solution prepared by dissolving 0.20 mole of cyanic acid (HCNO) and 0.80 mole of sodium cyanate (NaCNO) in enough water to make 1.0 liter of solution. [Ka(HCNO) = 2.0 × 10-4]


A) 0.97
B) 3.10
C) 4.40
D) 3.70
E) 4.30

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What is the pH at the equivalence point in the titration of 100 mL of 0.10 M HCN (Ka = 4.9 × 10-10) with 0.10 M NaOH?


A) 3.0
B) 6.0
C) 7.0
D) 11.0
E) 12.0

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Starting with 0.250L of a buffer solution containing 0.250 M benzoic acid (C6H5COOH) and 0.20 M sodium benzoate (C6H5COONa) , what will the pH of the solution be after the addition of 25.0 mL of 0.100M HCl? (Ka (C6H5COOH) = 6.5 x 10-5)


A) 4.19
B) 4.10
C) 4.28
D) 4.05
E) 3.78

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Calculate the molar solubility of lead (II)fluoride (Ksp (PbF2 = 4.1 x 10-8))

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Will a precipitate (ppt) form when 300.mL of 5.0 × 10-5 M AgNO3 are added to 200.mL of 2.5 × 10-7 M NaBr? Answer yes or no, and identify the precipitate if there is one.


A) Yes, the ppt is AgNO3(s) .
B) Yes, the ppt is AgBr(s) .
C) Yes, the ppt is NaBr(s) .
D) Yes, the ppt is NaNO3(s) .
E) No, a precipitate will not form.

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Starting with 0.750L of a buffer solution containing 0.30 M benzoic acid (C6H5COOH) and 0.35 M sodium benzoate (C6H5COONa) , what will the pH of the solution be after the addition of 340.0 mL of 0.350M HCl? (Ka (C6H5COOH) = 6.5 x 10-5)


A) 4.19
B) 4.25
C) 3.81
D) 0.45
E) 6.54

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The solubility product for chromium(III) fluoride is Ksp = 6.6 × 10-11.What is the molar solubility of chromium(III) fluoride?


A) 1.6 × 10-3 M
B) 1.2 × 10-3 M
C) 6.6 × 10-11 M
D) 2.2 × 10-3 M
E) 1.6 × 10-6 M

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Which of the following compounds is more soluble in acidic solution than in pure neutral water?


A) BaCO3
B) CuI
C) PbCl2
D) AgBr
E) NH4NO3

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Bromothymol blue is a common acid-base indicator.It has a Ka equal to 1.6 × 10-7.Its un-ionized form is yellow and its conjugate base is blue.What color would a solution have at pH = 5.8?

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Calculate the molar solubility of Mg(OH) 2 in a solution with pH = 12.20. (Ksp (Mg(OH) 2 = 1.2 x 10-11)


A) 4.8 x 10-8 M
B) 7.6 x 10-10 M
C) 3.5 x 10-6 M
D) 1.4 x 10-4 M
E) 2.4 x 10-6 M

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What mass of sodium fluoride must be added to 250.mL of a 0.100 M HF solution to give a buffer solution having a pH of 3.50? [Ka(HF) = 7.1 × 10-4]


A) 0.49 g
B) 1.5 g
C) 3.4 g
D) 2.3 g
E) 0.75 g

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For which type of titration will the pH be basic at the equivalence point?


A) Strong acid vs.strong base.
B) Strong acid vs.weak base.
C) Weak acid vs.strong base.
D) All of the above.
E) None of the above.

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The pH of a solution that is 0.20 M CH3COOH and 0.20 M CH3COONa should be higher than the pH of a 0.20 M CH3COOH solution.

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Describe how to prepare 500.mL of a cyanic acid (HCNO)/sodium cyanate (NaCNO)buffer having a pH of 4.80.[Ka(HCNO)= 2.0 × 10-4]

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Dissolve amounts of the two compounds eq...

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At 25 °C, the base ionization constant for NH3 is 1.8 × 10-5.Determine the hydroxide ion concentration in a 0.150 M solution of ammonia at 25 °C.

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What volume of 0.200 M potassium hydroxide should be added to 300.mL of 0.150 M propanoic acid (C2H5COOH) to obtain a solution with a pH of 5.25? [Ka(C2H5COOH) = 1.34 × 10-5]


A) 32 mL
B) 210 mL
C) 160 mL
D) 65 mL
E) 13 mL

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Calculate the silver ion concentration in a saturated solution of silver(I) carbonate (Ksp = 8.1 × 10-12) .


A) 5.0 × 10-5 M
B) 2.5 × 10-4 M
C) 1.3 × 10-4 M
D) 2.0 × 10-4 M
E) 8.1 × 10-4 M

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Will a precipitate (ppt) form when 20.0 mL of 1.1 × 10-3 M Ba(NO3) 2 are added to 80.0 mL of 8.4 × 10-4 M Na2CO3?


A) Yes, the ppt is Ba(NO3 ) 2.
B) Yes, the ppt is NaNO3.
C) Yes, the ppt is BaCO3.
D) Yes, the ppt is Na2CO3.
E) No, a precipitate will not form.

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