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What element is being oxidized in the following redox reaction? H2O2(l) + ClO2(aq) → ClO2-(aq) + O2(g)


A) H
B) O
C) Cl
D) N
E) C

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Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25°C. Pb2+(aq) + Cu(s) → Pb(s) + Cu2+(aq)


A) 7.9 × 10-8
B) 8.9 × 107
C) 7.9 × 1015
D) 1.3 × 10-16
E) 1.1 × 10-8

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Balance the following redox reaction if it occurs in basic solution.What are the coefficients in front of Cr(OH) 4 and ClO⁻ in the balanced reaction? Cr(OH) 4⁻(aq) + ClO⁻(aq) → CrO42-(aq) + Cl⁻(aq)


A) Cr(OH) 4⁻ = 2, ClO⁻ = 3
B) Cr(OH) 4⁻ = 1, ClO⁻ = 1
C) Cr(OH) 4⁻ = 1, ClO⁻ = 2
D) Cr(OH) 4⁻ = 2, ClO⁻ = 6
E) Cr(OH) 4⁻ = 6, ClO⁻ = 5

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The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2 H+(aq) → Zn2+(aq) + H2(g) With The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2 H<sup>+</sup>(aq) → Zn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  With   = 1.0 atm and [Zn<sup>2+</sup>] = 1.0 M,the cell potential is 0.66 V.The concentration of   in the cathode compartment is ________ M. A)  2.0 × 10<sup>-2</sup> B)  4.2 × 10<sup>-4</sup> C)  1.4 × 10<sup>-1</sup> D)  4.9 × 10<sup>1</sup> E)  1.0 × 10<sup>-12</sup> = 1.0 atm and [Zn2+] = 1.0 M,the cell potential is 0.66 V.The concentration of The standard cell potential (E°) of a voltaic cell constructed using the cell reaction below is 0.76 V: Zn(s) + 2 H<sup>+</sup>(aq) → Zn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  With   = 1.0 atm and [Zn<sup>2+</sup>] = 1.0 M,the cell potential is 0.66 V.The concentration of   in the cathode compartment is ________ M. A)  2.0 × 10<sup>-2</sup> B)  4.2 × 10<sup>-4</sup> C)  1.4 × 10<sup>-1</sup> D)  4.9 × 10<sup>1</sup> E)  1.0 × 10<sup>-12</sup> in the cathode compartment is ________ M.


A) 2.0 × 10-2
B) 4.2 × 10-4
C) 1.4 × 10-1
D) 4.9 × 101
E) 1.0 × 10-12

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Why,if we multiply a reaction by 2,don't we multiply its E°red by 2?

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Half-cell potentials (E°red)are a...

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Consider the following standard reduction potentials, Ni2+(aq) + 2 e- → Ni(s) E° = -0.26 V I2(s) + 2 e- → 2 I-(aq) E° = +0.54 V Under standard conditions,


A) Ni2+(aq) is a stronger oxidizing agent than I2(s) and I-(aq) is a stronger reducing agent than Ni(s) .
B) I2(s) is a stronger oxidizing agent than Ni2+(aq) and Ni(s) is a stronger reducing agent than I-(aq) .
C) Ni(s) is a stronger oxidizing agent than I-(aq) and Ni2+(aq) is a stronger reducing agent than I2(s) .
D) I-(aq) is a stronger oxidizing agent than Ni(s) and I2(s) is a stronger reducing agent than Ni2+(aq) .

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Use the tabulated half-cell potentials to calculate the equilibrium constant (K) for the following balanced redox reaction at 25°C. 3 I2(s) + 2 Fe(s) → 2 Fe3+(aq) + 6 I⁻(aq)


A) 3.5 × 10-59
B) 1.1 × 1017
C) 2.4 × 1058
D) 8.9 × 10-18
E) 1.7 × 1029

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What is the reaction at the cathode in a breathalyzer?


A) Ethanol is oxidized to acetic acid.
B) Acetic acid is reduced to ethanol.
C) Oxygen is reduced.
D) Hydrogen is oxidized.
E) Ethanol is oxidized to acetaldehyde.

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Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn2+(aq) + H2(g)


A) H+(aq) ∣ H2(g) ∣ Pt Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  A)  H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt   Sn(s)  ∣ Sn<sup>2+</sup>(aq)  B)  H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt   Sn<sup>2+</sup>(aq)  ∣ Sn(s)  C)  Sn<sup>2+</sup>(aq)  ∣ Sn(s)    H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt D)  Sn(s)  ∣ Sn<sup>2+</sup>(aq)    H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt E)  Sn(s)  ∣ H<sub>2</sub>(g)    Sn<sup>2+</sup>(aq)  ∣ H<sup>+</sup>(aq)  ∣ Pt Sn(s) ∣ Sn2+(aq)
B) H2(g) ∣ H+(aq) ∣ Pt Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  A)  H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt   Sn(s)  ∣ Sn<sup>2+</sup>(aq)  B)  H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt   Sn<sup>2+</sup>(aq)  ∣ Sn(s)  C)  Sn<sup>2+</sup>(aq)  ∣ Sn(s)    H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt D)  Sn(s)  ∣ Sn<sup>2+</sup>(aq)    H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt E)  Sn(s)  ∣ H<sub>2</sub>(g)    Sn<sup>2+</sup>(aq)  ∣ H<sup>+</sup>(aq)  ∣ Pt Sn2+(aq) ∣ Sn(s)
C) Sn2+(aq) ∣ Sn(s) Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  A)  H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt   Sn(s)  ∣ Sn<sup>2+</sup>(aq)  B)  H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt   Sn<sup>2+</sup>(aq)  ∣ Sn(s)  C)  Sn<sup>2+</sup>(aq)  ∣ Sn(s)    H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt D)  Sn(s)  ∣ Sn<sup>2+</sup>(aq)    H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt E)  Sn(s)  ∣ H<sub>2</sub>(g)    Sn<sup>2+</sup>(aq)  ∣ H<sup>+</sup>(aq)  ∣ Pt H2(g) ∣ H+(aq) ∣ Pt
D) Sn(s) ∣ Sn2+(aq) Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  A)  H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt   Sn(s)  ∣ Sn<sup>2+</sup>(aq)  B)  H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt   Sn<sup>2+</sup>(aq)  ∣ Sn(s)  C)  Sn<sup>2+</sup>(aq)  ∣ Sn(s)    H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt D)  Sn(s)  ∣ Sn<sup>2+</sup>(aq)    H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt E)  Sn(s)  ∣ H<sub>2</sub>(g)    Sn<sup>2+</sup>(aq)  ∣ H<sup>+</sup>(aq)  ∣ Pt H+(aq) ∣ H2(g) ∣ Pt
E) Sn(s) ∣ H2(g) Determine the cell notation for the redox reaction given below. Sn(s) + 2 H⁺(aq) → Sn<sup>2+</sup>(aq) + H<sub>2</sub>(g)  A)  H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt   Sn(s)  ∣ Sn<sup>2+</sup>(aq)  B)  H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt   Sn<sup>2+</sup>(aq)  ∣ Sn(s)  C)  Sn<sup>2+</sup>(aq)  ∣ Sn(s)    H<sub>2</sub>(g)  ∣ H<sup>+</sup>(aq)  ∣ Pt D)  Sn(s)  ∣ Sn<sup>2+</sup>(aq)    H<sup>+</sup>(aq)  ∣ H<sub>2</sub>(g)  ∣ Pt E)  Sn(s)  ∣ H<sub>2</sub>(g)    Sn<sup>2+</sup>(aq)  ∣ H<sup>+</sup>(aq)  ∣ Pt Sn2+(aq) ∣ H+(aq) ∣ Pt

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The standard emf for the cell using the overall cell reaction below is +0.48 V: Zn(s) + Ni2+(aq) → Zn2+(aq) + Ni(s) The emf generated by the cell when [Ni2+] = 2.50 M and [Zn2+] = 0.100 M is The standard emf for the cell using the overall cell reaction below is +0.48 V: Zn(s) + Ni<sup>2+</sup>(aq) → Zn<sup>2+</sup>(aq) + Ni(s)  The emf generated by the cell when [Ni<sup>2+</sup>] = 2.50 M and [Zn<sup>2+</sup>] = 0.100 M is   A)  0.40 B)  0.50 C)  0.52 D)  0.56 E)  0.44


A) 0.40
B) 0.50
C) 0.52
D) 0.56
E) 0.44

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Which of the following is the weakest reducing agent?


A) Br2(s)
B) ClO2-(aq)
C) Sn(s)
D) I⁻(aq)
E) Au(s)

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