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An infinitely long nonconducting cylinder of radius R = 2.00 cm carries a uniform volume charge density of 18.0 μC/ m3. Calculate the electric field at distance r = 1.00 cm from the axis of the cylinder. (ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 2.50 × 103 N/C
B) 5.10 × 103 N/C
C) zero
D) 2.00 × 103 N/C
E) 10.2 × 103 N/C

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A charge Q is uniformly spread over one surface of a very large nonconducting square elastic sheet having sides of length d. At a point P that is 1.25 cm outside the sheet, the magnitude of the electric field due to the sheet is E. If the sheet is now stretched so that its sides have length 2d, what is the magnitude of the electric field at P?


A) 4E
B) 2E
C) E
D) E/2
E) E/4

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If the electric flux through a closed surface is zero, the electric field at points on that surface must be zero.

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The cross section of a long coaxial cable is shown in the figure, with radii as given. The linear charge density on the inner conductor is -40 nC/m and the linear charge density on the outer conductor is -50 nC/m. The inner and outer cylindrical surfaces are respectively denoted by A, B, C, and D, as shown. (ε0 = 8.85 × 10-12 C2/N ∙ m2) The magnitude of the electric field at a point that is 94 mm from the axis is closest to The cross section of a long coaxial cable is shown in the figure, with radii as given. The linear charge density on the inner conductor is -40 nC/m and the linear charge density on the outer conductor is -50 nC/m. The inner and outer cylindrical surfaces are respectively denoted by A, B, C, and D, as shown. (ε0 = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)  The magnitude of the electric field at a point that is 94 mm from the axis is closest to   A)  17,000 N/C. B)  15,000 N/C. C)  13,000 N/C. D)  11,000 N/C. E)  9600 N/C.


A) 17,000 N/C.
B) 15,000 N/C.
C) 13,000 N/C.
D) 11,000 N/C.
E) 9600 N/C.

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Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upper sheet carries +5.00 µC/m2. The electric field midway between the sheets is 4.25 × 105 N/C pointing downward. What is the surface charge density on the lower sheet? (ε0 = 8.85 × 10-12 C2/N ∙ m2)

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Consider a spherical Gaussian surface of radius R centered at the origin. A charge Q is placed inside the sphere. To maximize the magnitude of the flux of the electric field through the Gaussian surface, the charge should be located


A) at x = 0, y = 0, z = R/2.
B) at the origin.
C) at x = R/2, y = 0, z = 0.
D) at x = 0, y = R/2, z = 0.
E) The charge can be located anywhere, since flux does not depend on the position of the charge as long as it is inside the sphere.

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A very large sheet of a conductor carries a uniform charge density of 4.00 pC/mm2 on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor? (ε0 = 8.85 × 10-12 C2/N ∙ m2)


A) 4.52 × 105 N/C
B) 2.26 × 105 N/C
C) 9.04 × 105 N/C
D) 0.452 N/C
E) 0.226 N/C

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An uncharged conductor has a hollow cavity inside of it. Within this cavity there is a charge of +10 µC that does not touch the conductor. There are no other charges in the vicinity. Which statement about this conductor is true? (There may be more than one correct choice.)


A) The inner surface of the conductor carries a charge of -10 µC and its outer surface carries no excess charge.
B) The inner and outer surfaces of the conductor each contain charges of -5 µC.
C) The net electric field within the material of the conductor points away from the +10 µC charge.
D) The outer surface of the conductor contains +10 µC of charge and the inner surface contains -10 µC.
E) Both surfaces of the conductor carry no excess charge because the conductor is uncharged.

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An irregular conductor carries a surface charge density of -6.75 µC/m2 at and in the vicinity of a point P on the surface. An electron is released just above P outside the conductor. What are the magnitude and direction of its acceleration the instant after it is released? (ε0 = 8.85 × 10-12 C2/N ∙ m2, e = 1.60 × 10-19 C, mel = 9.11 × 10-31 kg)

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1.34 × 1017 ...

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A hollow conducting spherical shell has radii of 0.80 m and 1.20 m, as shown in the figure. The sphere carries a net excess charge of -500 nC. A point charge of +300 nC is present at the center. (k = 1/4πε0 = 8.99 × 109 N ∙ m2/C) The radial component of the electric field at a point that is 0.60 m from the center is closest to A hollow conducting spherical shell has radii of 0.80 m and 1.20 m, as shown in the figure. The sphere carries a net excess charge of -500 nC. A point charge of +300 nC is present at the center. (k = 1/4πε0 = 8.99 × 10<sup>9</sup> N ∙ m<sup>2</sup>/C)  The radial component of the electric field at a point that is 0.60 m from the center is closest to   A)  zero. B)  +5000 N/C. C)  +7500 N/C. D)  -5000 N/C. E)  -7500 N/C.


A) zero.
B) +5000 N/C.
C) +7500 N/C.
D) -5000 N/C.
E) -7500 N/C.

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A nonuniform electric field is directed along the x-axis at all points in space. This magnitude of the field varies with x, but not with respect to y or z. The axis of a cylindrical surface, 0.80 m long and 0.20 m in diameter, is aligned parallel to the x-axis, as shown in the figure. The electric fields E1 and E2, at the ends of the cylindrical surface, have magnitudes of 9000 N/C and 5000 N/C respectively, and are directed as shown. (ε0 = 8.85 × 10-12 C2/N ∙ m2) The charge enclosed by the cylindrical surface is closest to A nonuniform electric field is directed along the x-axis at all points in space. This magnitude of the field varies with x, but not with respect to y or z. The axis of a cylindrical surface, 0.80 m long and 0.20 m in diameter, is aligned parallel to the x-axis, as shown in the figure. The electric fields E<sub>1</sub> and E<sub>2</sub>, at the ends of the cylindrical surface, have magnitudes of 9000 N/C and 5000 N/C respectively, and are directed as shown. (ε0 = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)  The charge enclosed by the cylindrical surface is closest to   A)  -1.1 nC. B)  1.1 nC. C)  -2.4 nC. D)  -4.8 nC. E)  4.8 nC.


A) -1.1 nC.
B) 1.1 nC.
C) -2.4 nC.
D) -4.8 nC.
E) 4.8 nC.

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Electric charge is uniformly distributed inside a nonconducting sphere of radius 0.30 m. The electric field at a point P, which is 0.50 m from the center of the sphere, is 15,000 N/C and is directed radially outward. What is the maximum magnitude of the electric field due to this sphere?


A) 25,000 N/C
B) 30,000 N/C
C) 36,000 N/C
D) 42,000 N/C
E) 48,000 N/C

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A solid nonconducting sphere of radius R carries a uniform charge density throughout its volume. At a radial distance r1 = R/4 from the center, the electric field has a magnitude E0. What is the magnitude of the electric field at a radial distance r2 = 2R?


A) E0/4
B) zero
C) E0/2
D) E0
E) 2E0

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A nonuniform electric field is directed along the x-axis at all points in space. This magnitude of the field varies with x, but not with respect to y or z. The axis of a cylindrical surface, 0.80 m long and 0.20 m in diameter, is aligned parallel to the x-axis, as shown in the figure. The electric fields E1 and E2, at the ends of the cylindrical surface, have magnitudes of 6000 N/C and 1000 N/C respectively, and are directed as shown. What is the net electric flux passing through the cylindrical surface? A nonuniform electric field is directed along the x-axis at all points in space. This magnitude of the field varies with x, but not with respect to y or z. The axis of a cylindrical surface, 0.80 m long and 0.20 m in diameter, is aligned parallel to the x-axis, as shown in the figure. The electric fields E<sub>1</sub> and E<sub>2</sub>, at the ends of the cylindrical surface, have magnitudes of 6000 N/C and 1000 N/C respectively, and are directed as shown. What is the net electric flux passing through the cylindrical surface?   A)  -160 N ∙ m<sup>2</sup>/C B)  -350 N ∙ m<sup>2</sup>/C C)  0.00 N ∙ m<sup>2</sup>/C D)  +350 N ∙ m<sup>2</sup>/C E)  +160 N ∙ m<sup>2</sup>/C


A) -160 N ∙ m2/C
B) -350 N ∙ m2/C
C) 0.00 N ∙ m2/C
D) +350 N ∙ m2/C
E) +160 N ∙ m2/C

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The figure shows four Gaussian surfaces surrounding a distribtuion of charges. The figure shows four Gaussian surfaces surrounding a distribtuion of charges.   (a) Which Gaussian surfaces have an electric flux of +q/ε0 through them? (b) Which Gaussian surfaces have no electric flux through them? (a) Which Gaussian surfaces have an electric flux of +q/ε0 through them? (b) Which Gaussian surfaces have no electric flux through them?

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The cross section of a long coaxial cable is shown in the figure, with radii as given. The linear charge density on the inner conductor is -30 nC/m and the linear charge density on the outer conductor is -70 nC/m. The inner and outer cylindrical surfaces are respectively denoted by A, B, C, and D, as shown. (ε0 = 8.85 × 10-12 C2/N ∙ m2) The radial component of the electric field at a point that 34 mm from the axis is closest to The cross section of a long coaxial cable is shown in the figure, with radii as given. The linear charge density on the inner conductor is -30 nC/m and the linear charge density on the outer conductor is -70 nC/m. The inner and outer cylindrical surfaces are respectively denoted by A, B, C, and D, as shown. (ε0 = 8.85 × 10<sup>-12 </sup>C<sup>2</sup>/N ∙ m<sup>2</sup>)  The radial component of the electric field at a point that 34 mm from the axis is closest to   A)  -16,000 N/C. B)  +16,000 N/C. C)  -37,000 N/C. D)  +37,000 N/C. E)  zero


A) -16,000 N/C.
B) +16,000 N/C.
C) -37,000 N/C.
D) +37,000 N/C.
E) zero

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The cube of insulating material shown in the figure has one corner at the origin. Each side of the cube has length 0.080 m so the top face of the cube is parallel to the xz-plane and is at y = 0.080 m. It is observed that there is an electric field The cube of insulating material shown in the figure has one corner at the origin. Each side of the cube has length 0.080 m so the top face of the cube is parallel to the xz-plane and is at y = 0.080 m. It is observed that there is an electric field    that is in the +y direction and whose magnitude depends only on y. Use Gauss's law to calculate the net charge enclosed by the cube. (ε0 = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)  that is in the +y direction and whose magnitude depends only on y. Use Gauss's law to calculate the net charge enclosed by the cube. (ε0 = 8.85 × 10-12 C2/N ∙ m2) The cube of insulating material shown in the figure has one corner at the origin. Each side of the cube has length 0.080 m so the top face of the cube is parallel to the xz-plane and is at y = 0.080 m. It is observed that there is an electric field    that is in the +y direction and whose magnitude depends only on y. Use Gauss's law to calculate the net charge enclosed by the cube. (ε0 = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)

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Four dipoles, each consisting of a +10-µC charge and a -10-µC charge, are located in the xy-plane with their centers 1.0 mm from the origin, as shown. A sphere passes through the dipoles, as shown in the figure. What is the electric flux through the sphere due to these dipoles? (ε0 = 8.85 × 10-12 C2/N ∙ m2) Four dipoles, each consisting of a +10-µC charge and a -10-µC charge, are located in the xy-plane with their centers 1.0 mm from the origin, as shown. A sphere passes through the dipoles, as shown in the figure. What is the electric flux through the sphere due to these dipoles? (ε0 = 8.85 × 10<sup>-12</sup> C<sup>2</sup>/N ∙ m<sup>2</sup>)    A)  4.5 × 10<sup>6</sup> N ∙ m<sup>2</sup>/C B)  0.00 N ∙ m<sup>2</sup>/C C)  9.0 × 10<sup>6 </sup>N ∙ m<sup>2</sup>/C D)  11 × 10<sup>5</sup> N ∙ m<sup>2</sup>/C


A) 4.5 × 106 N ∙ m2/C
B) 0.00 N ∙ m2/C
C) 9.0 × 106 N ∙ m2/C
D) 11 × 105 N ∙ m2/C

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As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m × 2.0 m has a charge of 8.0 × 10-11 C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (ε0 = 8.85 × 10-12 C2/N ∙ m2) As shown in the figure, a square insulating slab 5.0 mm thick measuring 2.0 m × 2.0 m has a charge of 8.0 × 10<sup>-11</sup> C distributed uniformly throughout its volume. Use Gauss's law to determine the electric field at point P, which is located within the slab beneath its center, 1.0 mm from one of the faces. (ε0 = 8.85 × 10<sup>-12 </sup>C<sup>2</sup>/N ∙ m<sup>2</sup>)    A)  0.68 N/C B)  14 N/C C)  23 N/C D)  34 N/C E)  57 N/C


A) 0.68 N/C
B) 14 N/C
C) 23 N/C
D) 34 N/C
E) 57 N/C

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If a rectangular area is rotated in a uniform electric field from the position where the maximum electric flux goes through it to an orientation where only half the flux goes through it, what has been the angle of rotation?


A) 45°
B) 26.6°
C) 90°
D) 30°
E) 60°

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