Question 1

Convert the rectangular equation to polar form.Assume r > 1.​  y=2y = 2y=2  ​

Accepted Answer

A)    r=2cos⁡θr = 2 \cos 	hetar=2cosθ 
B)    r=csc⁡θr = \csc 	hetar=cscθ 
C)    r=2csc⁡θr = 2 \csc 	hetar=2cscθ 
D)    r=2sin⁡θr = 2 \sin 	hetar=2sinθ 
E)    r=2sec⁡θr = 2 \sec 	hetar=2secθ

Question 2

Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​  r=2r = 2r=2  ​

Accepted Answer

A)  The graph of the polar equation consists of all points that are two units from the pole.  x2+y2=−4x ^ { 2 } + y ^ { 2 } = - 4x2+y2=−4  
B)  The graph of the polar equation consists of all points that are two units from the pole.  x2+y2=4x ^ { 2 } + y ^ { 2 } = 4x2+y2=4  
C)  The graph of the polar equation consists of all points that are two units from the pole.  x2+y2=2x ^ { 2 } + y ^ { 2 } = 2x2+y2=2  
D)  The graph of the polar equation consists of all points that are two units from the pole.  x2+y2=4x ^ { 2 } + y ^ { 2 } = 4x2+y2=4  
E)  The graph of the polar equation consists of all points that are two units from the pole.  x2+y2=2x ^ { 2 } + y ^ { 2 } = 2x2+y2=2

Question 3

A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​  (−19,19) ( - \sqrt { 19 } , \sqrt { 19 } ) (−19​,19​)   ​

Accepted Answer

A)  Polar coordinates:  (38,3π4) \left( \sqrt { 38 } , \frac { 3 \pi } { 4 } \right) (38c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,43π​)  
B)  Polar coordinates:  (38,−π4) \left( \sqrt { 38 } , - \frac { \pi } { 4 } \right) (38c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,−4π​)  
C)  Polar coordinates:  (38,−3π4) \left( \sqrt { 38 } , - \frac { 3 \pi } { 4 } \right) (38c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,−43π​)  
D)  Polar coordinates:  (38,π4) \left( \sqrt { 38 } , \frac { \pi } { 4 } \right) (38c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,4π​)  
E)  Polar coordinates:  (38,5π4) \left( \sqrt { 38 } , \frac { 5 \pi } { 4 } \right) (38c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,45π​)

Question 4

Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​  (3.5,1.62) ( 3.5,1.62 ) (3.5,1.62)   ​

Accepted Answer

A)  Rectangular coordinates: (3.5,1.62) 
B)  Rectangular coordinates: (4.50,0.83) 
C)  Rectangular coordinates: (-0.17,3.50) 
D)  Rectangular coordinates: (0.83,4.50) 
E)  Rectangular coordinates: (3.50,-0.17)

Question 5

A point (a,b) shown in below graph in polar coordinates is given.Convert the point to rectangular coordinates.​  ​  a=3,b=3π2a = 3 , b = \frac { 3 \pi } { 2 }a=3,b=23π​  ​

Accepted Answer

A)  Rectangular coordinates: (0,3) 
B)  Rectangular coordinates: (-3,0) 
C)  Rectangular coordinates: (3,0) 
D)  Rectangular coordinates: (0,-3) 
E)  Rectangular coordinates: (3,3)

Question 6

Convert the rectangular equation to polar form.Assume r > 1.​  x2+y2=49x ^ { 2 } + y ^ { 2 } = 49x2+y2=49  ​

Accepted Answer

A)    r=7r = 7r=7 
B)    r=−7r = - 7r=−7 
C)    r=17r = \frac { 1 } { 7 }r=71​ 
D)    r=49r = 49r=49 
E)    r=−17r = - \frac { 1 } { 7 }r=−71​

Question 7

Convert the rectangular equation to polar form.Assume r > 1.​  x=17ax = 17 ax=17a  ​

Accepted Answer

A)    r=acsc⁡θr = \operatorname { acsc } 	hetar=acscθ 
B)    r=17acos⁡θr = 17 \mathrm { a } \cos 	hetar=17acosθ 
C)    r=17sin⁡θr = 17 \sin 	hetar=17sinθ 
D)    r=17acsc⁡θr = 17 \operatorname { acsc } 	hetar=17acscθ 
E)    r=17 asec θr = 17 	ext { asec } 	hetar=17 asec θ

Question 8

Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​  (8,7π5) \left( 8 , \frac { 7 \pi } { 5 } \right) (8,57π​)   ​

Accepted Answer

A)  Rectangular coordinates: (7.61,0.07) 
B)  Rectangular coordinates: (7.61,-7.61) 
C)  Rectangular coordinates: (-2.47,-7.61) 
D)  Rectangular coordinates: (-2.47,7.61) 
E)  Rectangular coordinates: (-2.47,0.07)

Question 9

Convert the rectangular equation to polar form.Assume r > 1.​  (x2+y2) 2=9(x2−y2) \left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 2 } = 9 \left( x ^ { 2 } - y ^ { 2 } \right) (x2+y2) 2=9(x2−y2)   ​

Accepted Answer

A)    r2=9cos⁡2θr ^ { 2 } = 9 \cos 2 	hetar2=9cos2θ 
B)    r2=9csc⁡2θr ^ { 2 } = 9 \csc 2 	hetar2=9csc2θ 
C)    r2=9cos⁡θr ^ { 2 } = 9 \cos 	hetar2=9cosθ 
D)    r2=9sin⁡2θr ^ { 2 } = 9 \sin 2 	hetar2=9sin2θ 
E)    r2=9sin⁡θr ^ { 2 } = 9 \sin 	hetar2=9sinθ

Question 10

A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​  (−6,3.56) ( - 6,3.56 ) (−6,3.56)   ​

Accepted Answer

A)  Rectangular coordinates: (3.6,6.0) 
B)  Rectangular coordinates: (5.5,2.4) 
C)  Rectangular coordinates: (-5.5,-2.4) 
D)  Rectangular coordinates: (-2.4,-5.5) 
E)  Rectangular coordinates: (2.4,5.5)

Question 11

Convert the polar equation to rectangular form.​  r=−9sec⁡θr = - 9 \sec 	hetar=−9secθ  ​

Accepted Answer

A)    y=−9y = - 9y=−9 
B)    9x=r9 x = r9x=r 
C)    x=9x = 9x=9 
D)    y=9y = 9y=9 
E)    x=−9x = - 9x=−9

Question 12

Convert the rectangular equation to polar form.Assume r > 1.​  y=6y = 6y=6  ​

Accepted Answer

A)    r=6csc⁡θr = 6 \csc 	hetar=6cscθ 
B)    r=6cos⁡θr = 6 \cos 	hetar=6cosθ 
C)    r=6cot⁡θr = 6 \cot 	hetar=6cotθ 
D)    r=6sin⁡θr = 6 \sin 	hetar=6sinθ 
E)    r=6sec⁡θr = 6 \sec 	hetar=6secθ

Question 13

A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​  (−7,7) ( - 7,7 ) (−7,7)   ​

Accepted Answer

A)  Polar coordinates:  (−7,π4) \left( - \sqrt { 7 } , \frac { \pi } { 4 } \right) (−7c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,4π​)  
B)  Polar coordinates:  (98,3π4) \left( \sqrt { 98 } , \frac { 3 \pi } { 4 } \right) (98c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,43π​)  
C)  Polar coordinates:  (98,−3π4) \left( \sqrt { 98 } , - \frac { 3 \pi } { 4 } \right) (98c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,−43π​)  
D)  Polar coordinates:  (−98,3π4) \left( - \sqrt { 98 } , \frac { 3 \pi } { 4 } \right) (−98c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,43π​)  
E)  Polar coordinates:  (7,π4) \left( \sqrt { 7 } , \frac { \pi } { 4 } \right) (7c-2.7,0,-7.17,-2.7,-13.5,-8c-5.8,-5.3,-9.5,-10,-9.5,-14c0,-2,0.3,-3.3,1,-4c1.3,-2.7,23.83,-20.7,67.5,-54c44.2,-33.3,65.8,-50.3,66.5,-51c1.3,-1.3,3,-2,5,-2c4.7,0,8.7,3.3,12,10s173,378,173,378c0.7,0,35.3,-71,104,-213c68.7,-142,137.5,-285,206.5,-429c69,-144,104.5,-217.7,106.5,-221l0 -0c5.3,-9.3,12,-14,20,-14H400000v40H845.2724s-225.272,467,-225.272,467s-235,486,-235,486c-2.7,4.7,-9,7,-19,7c-6,0,-10,-1,-12,-3s-194,-422,-194,-422s-65,47,-65,47zM834 80h400000v40h-400000z'/>​,4π​)

Question 14

A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​  (−2.1,1.1) ( - 2.1,1.1 ) (−2.1,1.1)   ​

Accepted Answer

A)  Rectangular coordinates: (1.9,1.0) 
B)  Rectangular coordinates: (-1.0,-1.9) 
C)  Rectangular coordinates: (2.1,1.1) 
D)  Rectangular coordinates: (-1.9,-1.0) 
E)  Rectangular coordinates: (1.0,1.9)

Question 15

Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​  r=2sec⁡θr = 2 \sec 	hetar=2secθ  ​

Accepted Answer

A)  The graph of the polar equation is not evident by simple inspection.Convert to rectangular form first.​  x−5=0x - 5 = 0x−5=0  ​ 
B)  The graph of the polar equation is not evident by simple inspection.Convert to rectangular form first.​  x−2=0x - 2 = 0x−2=0  ​ 
C)  The graph of the polar equation is not evident by simple inspection.Convert to rectangular form first.​  x+2=0x + 2 = 0x+2=0  ​ 
D)  The graph of the polar equation is not evident by simple inspection.Convert to rectangular form first.​  x−3=0x - 3 = 0x−3=0  ​​ 
E)  The graph of the polar equation is not evident by simple inspection.Convert to rectangular form first.​  x−3=0x - 3 = 0x−3=0  ​

Question 16

Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​  (8.98,3.0) ( 8.98,3.0 ) (8.98,3.0)   ​

Accepted Answer

A)  Rectangular coordinates: (2.27,-7.89) 
B)  Rectangular coordinates: (-7.89,2.27) 
C)  Rectangular coordinates: (1.27,-8.89) 
D)  Rectangular coordinates: (-8.89,1.27) 
E)  Rectangular coordinates: (8.98,4.50)

Question 17

Convert the polar equation to rectangular form.​  r=2sin⁡θr = 2 \sin 	hetar=2sinθ  ​

Accepted Answer

A)    x2+y2−2y=0x ^ { 2 } + y ^ { 2 } - 2 y = 0x2+y2−2y=0 
B)    x2+y2+2y=0x ^ { 2 } + y ^ { 2 } + 2 y = 0x2+y2+2y=0 
C)    x2+y2−2x=0x ^ { 2 } + y ^ { 2 } - 2 \mathrm { x } = 0x2+y2−2x=0 
D)    x2+y2+2x=0x ^ { 2 } + y ^ { 2 } + 2 \mathrm { x } = 0x2+y2+2x=0 
E)    x2+y2−2=0x ^ { 2 } + y ^ { 2 } - 2 = 0x2+y2−2=0

Question 18

Convert the polar equation to rectangular form.​  r=6cos⁡2θr = 6 \cos 2 	hetar=6cos2θ  ​

Accepted Answer

A)    (x2+y2) 2=36(x2−y2) 2\left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 2 } = 36 \left( x ^ { 2 } - y ^ { 2 } \right)  ^ { 2 }(x2+y2) 2=36(x2−y2) 2 
B)    (x2+y2) 3=6(x2−y2) 3\left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 3 } = 6 \left( x ^ { 2 } - y ^ { 2 } \right)  ^ { 3 }(x2+y2) 3=6(x2−y2) 3 
C)    (x2+y2) 3=36(x2−y2) 3\left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 3 } = 36 \left( x ^ { 2 } - y ^ { 2 } \right)  ^ { 3 }(x2+y2) 3=36(x2−y2) 3 
D)    (x2+y2) 3=6(x2−y2) 2\left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 3 } = 6 \left( x ^ { 2 } - y ^ { 2 } \right)  ^ { 2 }(x2+y2) 3=6(x2−y2) 2 
E)    (x2+y2) 3=36(x2−y2) 2\left( x ^ { 2 } + y ^ { 2 } \right)  ^ { 3 } = 36 \left( x ^ { 2 } - y ^ { 2 } \right)  ^ { 2 }(x2+y2) 3=36(x2−y2) 2

Question 19

Convert the polar equation to rectangular form.​  r=4csc⁡θr = 4 \csc 	hetar=4cscθ  ​

Accepted Answer

A)    y=4y = 4y=4 
B)    y=4ry = 4 \mathrm { r }y=4r 
C)    x=4x = 4x=4 
D)    6y=r6 y = \mathrm { r }6y=r 
E)    x=4rx = 4 \mathrm { r }x=4r

Question 20

Convert the rectangular equation to polar form.Assume a > 0,r > 1.​  x2+y2=4a2x ^ { 2 } + y ^ { 2 } = 4 a ^ { 2 }x2+y2=4a2  ​

Accepted Answer

A)    r=2ar = 2 ar=2a 
B)    r=−42ar = - 42 ar=−42a 
C)    r=2r = 2r=2 
D)    r=−2a2r = - 2 a ^ { 2 }r=−2a2 
E)    r=2a2r = 2 a ^ { 2 }r=2a2

Exam 65: Polar Coordinates

Convert the rectangular equation to polar form.Assume r > 1. $y = 2$

Correct Answer
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Convert the polar equation to rectangular form. $r = 4 \csc \theta$

Correct Answer
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Convert the polar equation to rectangular form. $r = - 9 \sec \theta$

Correct Answer
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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0. $( - \sqrt { 19 } , \sqrt { 19 } )$

Correct Answer
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Convert the polar equation to rectangular form. $r = 6 \cos 2 \theta$

Correct Answer
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Convert the rectangular equation to polar form.Assume r > 1. $x ^ { 2 } + y ^ { 2 } = 49$

Correct Answer
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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $\left( 8 , \frac { 7 \pi } { 5 } \right)$

Correct Answer
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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph. $r = 2$

Correct Answer
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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places. $( - 6,3.56 )$

Correct Answer
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Convert the rectangular equation to polar form.Assume a > 0,r > 1. $x ^ { 2 } + y ^ { 2 } = 4 a ^ { 2 }$

Correct Answer
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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $( 8.98,3.0 )$

Correct Answer
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Correct Answer
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Convert the polar equation to rectangular form. $r = 2 \sin \theta$

Correct Answer
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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places. $( - 2.1,1.1 )$

Correct Answer
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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0. $( - 7,7 )$

Correct Answer
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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph. $r = 2 \sec \theta$

Correct Answer
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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $( 3.5,1.62 )$

Correct Answer
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Convert the rectangular equation to polar form.Assume r > 1. $\left( x ^ { 2 } + y ^ { 2 } \right) ^ { 2 } = 9 \left( x ^ { 2 } - y ^ { 2 } \right)$

Correct Answer
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Convert the rectangular equation to polar form.Assume r > 1. $x = 17 a$

Correct Answer
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Convert the rectangular equation to polar form.Assume r > 1. $y = 6$

Correct Answer
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Exam 65: Polar Coordinates

Convert the rectangular equation to polar form.Assume r > 1.​ y=2y = 2y=2 ​

Correct AnswerverifiedShow Answer

Convert the polar equation to rectangular form.​ r=4csc⁡θr = 4 \csc \thetar=4cscθ ​

Correct AnswerverifiedShow Answer

Convert the polar equation to rectangular form.​ r=−9sec⁡θr = - 9 \sec \thetar=−9secθ ​

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​ (−19,19) ( - \sqrt { 19 } , \sqrt { 19 } ) (−19​,19​) ​

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Convert the polar equation to rectangular form.​ r=6cos⁡2θr = 6 \cos 2 \thetar=6cos2θ ​

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Convert the rectangular equation to polar form.Assume r > 1.​ x2+y2=49x ^ { 2 } + y ^ { 2 } = 49x2+y2=49 ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (8,7π5) \left( 8 , \frac { 7 \pi } { 5 } \right) (8,57π​) ​

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​ r=2r = 2r=2 ​

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​ (−6,3.56) ( - 6,3.56 ) (−6,3.56) ​

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Convert the rectangular equation to polar form.Assume a > 0,r > 1.​ x2+y2=4a2x ^ { 2 } + y ^ { 2 } = 4 a ^ { 2 }x2+y2=4a2 ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (8.98,3.0) ( 8.98,3.0 ) (8.98,3.0) ​

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A point (a,b) shown in below graph in polar coordinates is given.Convert the point to rectangular coordinates.​ ​ a=3,b=3π2a = 3 , b = \frac { 3 \pi } { 2 }a=3,b=23π​ ​

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Convert the polar equation to rectangular form.​ r=2sin⁡θr = 2 \sin \thetar=2sinθ ​

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places.​ (−2.1,1.1) ( - 2.1,1.1 ) (−2.1,1.1) ​

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0.​ (−7,7) ( - 7,7 ) (−7,7) ​

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph.​ r=2sec⁡θr = 2 \sec \thetar=2secθ ​

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places.​ (3.5,1.62) ( 3.5,1.62 ) (3.5,1.62) ​

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Convert the rectangular equation to polar form.Assume r > 1.​ (x2+y2) 2=9(x2−y2) \left( x ^ { 2 } + y ^ { 2 } \right) ^ { 2 } = 9 \left( x ^ { 2 } - y ^ { 2 } \right) (x2+y2) 2=9(x2−y2) ​

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Convert the rectangular equation to polar form.Assume r > 1.​ x=17ax = 17 ax=17a ​

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Convert the rectangular equation to polar form.Assume r > 1.​ y=6y = 6y=6 ​

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Convert the rectangular equation to polar form.Assume r > 1. $y = 2$

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Convert the polar equation to rectangular form. $r = 4 \csc \theta$

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Convert the polar equation to rectangular form. $r = - 9 \sec \theta$

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0. $( - \sqrt { 19 } , \sqrt { 19 } )$

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Convert the polar equation to rectangular form. $r = 6 \cos 2 \theta$

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Convert the rectangular equation to polar form.Assume r > 1. $x ^ { 2 } + y ^ { 2 } = 49$

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $\left( 8 , \frac { 7 \pi } { 5 } \right)$

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph. $r = 2$

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places. $( - 6,3.56 )$

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Convert the rectangular equation to polar form.Assume a > 0,r > 1. $x ^ { 2 } + y ^ { 2 } = 4 a ^ { 2 }$

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $( 8.98,3.0 )$

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Convert the polar equation to rectangular form. $r = 2 \sin \theta$

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A point in polar coordinates is given.Convert the point to rectangular coordinates.Round your answers to one decimal places. $( - 2.1,1.1 )$

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A point in rectangular coordinates is given.Convert the point to polar coordinates,r > 0. $( - 7,7 )$

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Describe the graph of the polar equation and find the corresponding rectangular equation.Select the correct graph. $r = 2 \sec \theta$

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Find the rectangular coordinates of the point given in polar coordinates.Round your results to two decimal places. $( 3.5,1.62 )$

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Convert the rectangular equation to polar form.Assume r > 1. $\left( x ^ { 2 } + y ^ { 2 } \right) ^ { 2 } = 9 \left( x ^ { 2 } - y ^ { 2 } \right)$

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Convert the rectangular equation to polar form.Assume r > 1. $x = 17 a$

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Convert the rectangular equation to polar form.Assume r > 1. $y = 6$

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