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If we are testing the hypothesis about the mean of a population of paired differences with samples of n1 = 10,n2 = 10,the degrees of freedom for the t statistic is ____.


A) 20
B) 9
C) 18
D) 10

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In forming a confidence interval for In forming a confidence interval for ,only two assumptions are required: independent samples and sample sizes of at least 30. ,only two assumptions are required: independent samples and sample sizes of at least 30.

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When comparing the variances of two normally distributed populations using independent random samples,if When comparing the variances of two normally distributed populations using independent random samples,if ,the calculated value of F will always be equal to one. ,the calculated value of F will always be equal to one.

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Find a 95 percent confidence interval for the difference between means where n1 = 50,n2= 36, Find a 95 percent confidence interval for the difference between means where n<sub>1</sub> = 50,n<sub>2</sub>= 36, <sub>1</sub> = 80, <sub>2</sub> = 75, \sigma <sub>1</sub><sup>2</sup> = 5 and \sigma <sub>2</sub><sup>2</sup> = 3. A) (4.16 5.84) B) (3.30 6.70) C) (4.40 5.60) D) (4.64 5.36) 1 = 80, Find a 95 percent confidence interval for the difference between means where n<sub>1</sub> = 50,n<sub>2</sub>= 36, <sub>1</sub> = 80, <sub>2</sub> = 75, \sigma <sub>1</sub><sup>2</sup> = 5 and \sigma <sub>2</sub><sup>2</sup> = 3. A) (4.16 5.84) B) (3.30 6.70) C) (4.40 5.60) D) (4.64 5.36) 2 = 75, σ\sigma 12 = 5 and σ\sigma 22 = 3.


A) (4.16 5.84)
B) (3.30 6.70)
C) (4.40 5.60)
D) (4.64 5.36)

Correct Answer

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When comparing the variances of two normally distributed populations using independent random samples,the correct test statistic to use is __________.


A) Z
B) t
C) F
D) Chi-square
E) None of the above

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Find a 90 percent confidence interval for the difference between the proportions of Group l and Group 2.Let p1 represent the population proportion of the people in group 1 who are in favor of new packaging and Let p2 represent the population proportion of the people in group 2 who are in favor of new packaging,where Find a 90 percent confidence interval for the difference between the proportions of Group l and Group 2.Let p<sub>1</sub> represent the population proportion of the people in group 1 who are in favor of new packaging and Let p<sub>2</sub> represent the population proportion of the people in group 2 who are in favor of new packaging,where <sub>1</sub> = .21, <sub>2</sub> = .13,n<sub>1</sub>= 300,n<sub>2</sub> = 400. A) (.0472 .1128) B) (.0510 .1090) C) (.0232 .1368) D) (.0324 .1276) 1 = .21, Find a 90 percent confidence interval for the difference between the proportions of Group l and Group 2.Let p<sub>1</sub> represent the population proportion of the people in group 1 who are in favor of new packaging and Let p<sub>2</sub> represent the population proportion of the people in group 2 who are in favor of new packaging,where <sub>1</sub> = .21, <sub>2</sub> = .13,n<sub>1</sub>= 300,n<sub>2</sub> = 400. A) (.0472 .1128) B) (.0510 .1090) C) (.0232 .1368) D) (.0324 .1276) 2 = .13,n1= 300,n2 = 400.


A) (.0472 .1128)
B) (.0510 .1090)
C) (.0232 .1368)
D) (.0324 .1276)

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Find a 95 percent confidence interval for µ1- µ2,where n1= 9,n2 = 6, Find a 95 percent confidence interval for µ<sub>1</sub>- µ<sub>2</sub>,where n<sub>1</sub>= 9,n<sub>2</sub> = 6, <sub>1</sub> = 64, <sub>2</sub> = 59,s<sub>1</sub><sup>2</sup> = 6 and s<sub>2</sub><sup>2</sup> = 3.(Assume equal population variances) A) (2.357 7.643) B) (2.494 7.506) C) (2.528 7.472) D) (3.840 6.160) 1 = 64, Find a 95 percent confidence interval for µ<sub>1</sub>- µ<sub>2</sub>,where n<sub>1</sub>= 9,n<sub>2</sub> = 6, <sub>1</sub> = 64, <sub>2</sub> = 59,s<sub>1</sub><sup>2</sup> = 6 and s<sub>2</sub><sup>2</sup> = 3.(Assume equal population variances) A) (2.357 7.643) B) (2.494 7.506) C) (2.528 7.472) D) (3.840 6.160) 2 = 59,s12 = 6 and s22 = 3.(Assume equal population variances)


A) (2.357 7.643)
B) (2.494 7.506)
C) (2.528 7.472)
D) (3.840 6.160)

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An experiment in which two different measurements are taken on the same units and inferences are made using the differences between the pairs of measurements is a(n) ______ experiment.


A) Paired difference
B) Equal variances
C) Independent samples
D) Dependent samples

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Find a 99 percent confidence interval for the difference between means n1 = 49,n2 = 49, Find a 99 percent confidence interval for the difference between means n<sub>1</sub> = 49,n<sub>2</sub> = 49, <sub>1</sub> = 87, <sub>2</sub> = 92, \sigma <sub>1</sub><sup>2</sup> = 13 and \sigma <sub>2</sub><sup>2</sup> = 15. A) (-12.30 2.30) B) (-6.47 -3.53) C) (-6.94 -3.05) D) (-5.57 -4.43) 1 = 87, Find a 99 percent confidence interval for the difference between means n<sub>1</sub> = 49,n<sub>2</sub> = 49, <sub>1</sub> = 87, <sub>2</sub> = 92, \sigma <sub>1</sub><sup>2</sup> = 13 and \sigma <sub>2</sub><sup>2</sup> = 15. A) (-12.30 2.30) B) (-6.47 -3.53) C) (-6.94 -3.05) D) (-5.57 -4.43) 2 = 92, σ\sigma 12 = 13 and σ\sigma 22 = 15.


A) (-12.30 2.30)
B) (-6.47 -3.53)
C) (-6.94 -3.05)
D) (-5.57 -4.43)

Correct Answer

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When testing a hypothesis about the mean of a population of paired differences in which two different observations are taken on the same units,the correct test statistic to use is:


A) Z
B) t
C) F
D) Chi-square
E) None of the above

Correct Answer

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A coffee shop franchise owner is looking at two possible locations for a new shop.To help make a decision he looks at the number of pedestrians that go by each of the two locations in one-hour segments.At location A,counts are taken for 35 one-hour units and with a mean number of pedestrians of 421 and a sample standard deviation of 122.At the second location (B) ,counts are taken for 50 one hour units with a mean number of pedestrians of 347 and a sample standard deviation of 85.Assume the two populations variances are not known but are equal.Calculate the pooled estimate of A coffee shop franchise owner is looking at two possible locations for a new shop.To help make a decision he looks at the number of pedestrians that go by each of the two locations in one-hour segments.At location A,counts are taken for 35 one-hour units and with a mean number of pedestrians of 421 and a sample standard deviation of 122.At the second location (B) ,counts are taken for 50 one hour units with a mean number of pedestrians of 347 and a sample standard deviation of 85.Assume the two populations variances are not known but are equal.Calculate the pooled estimate of . A) 10362.42 B) 101.80 C) 22.40 D) 503.32 .


A) 10362.42
B) 101.80
C) 22.40
D) 503.32

Correct Answer

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When comparing two independent population means when population variances are not known and the samples are normally distributed,the correct test statistic to use is ____.


A) Z
B) t
C) F
D) t2

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A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat.The data are given below. A marketing research company surveyed grocery shoppers in the east and west coasts to see the percentage of the customers who prefer chicken to other meat.The data are given below. What is the test statistic for this hypothesis test? A) 1.645 B) 3.92 C) 1.96 D) 3.09 What is the test statistic for this hypothesis test?


A) 1.645
B) 3.92
C) 1.96
D) 3.09

Correct Answer

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Find a 95 percent confidence interval for the difference between the proportions of older and younger drivers who have tickets where Find a 95 percent confidence interval for the difference between the proportions of older and younger drivers who have tickets where <sub>1</sub> = .275, <sub>2</sub> = .25,n<sub>1</sub>= 1000,n<sub>2</sub> = 1000. A) (-.007 .057) B) (.024 .026) C) (-.002 .052) D) (-.014 .064) 1 = .275, Find a 95 percent confidence interval for the difference between the proportions of older and younger drivers who have tickets where <sub>1</sub> = .275, <sub>2</sub> = .25,n<sub>1</sub>= 1000,n<sub>2</sub> = 1000. A) (-.007 .057) B) (.024 .026) C) (-.002 .052) D) (-.014 .064) 2 = .25,n1= 1000,n2 = 1000.


A) (-.007 .057)
B) (.024 .026)
C) (-.002 .052)
D) (-.014 .064)

Correct Answer

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What is the value of the F-statistic for H0: σ\sigma 12 ≤\le σ\sigma 12,HA: σ\sigma 12> σ\sigma 12,where s1= 3.3,and s2 = 2.1.


A) 2.47
B) 1.57
C) 6.48
D) 6.10

Correct Answer

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In testing the difference between two independent population means if the variances of the two populations are not equal the critical value of the t statistic is obtained by calculating ___________________.


A) degrees of freedom
B) the sum of the two sample sizes (n1 + n2)
C) p-value
D) pooled variance

Correct Answer

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In an opinion survey,a random sample of 1000 adults from the U.S.A and 1000 adults from Germany were asked whether they supported the death penalty.590 American adults and 560 German adults indicated that they supported the death penalty.The researcher wants to know if there is sufficient evidence to conclude that the proportion of adults who support the death penalty is higher in the U.S.A.than in Germany.What is the decision at In an opinion survey,a random sample of 1000 adults from the U.S.A and 1000 adults from Germany were asked whether they supported the death penalty.590 American adults and 560 German adults indicated that they supported the death penalty.The researcher wants to know if there is sufficient evidence to conclude that the proportion of adults who support the death penalty is higher in the U.S.A.than in Germany.What is the decision at = .10? A) Reject the null hypothesis B) Can't reject the null hypothesis = .10?


A) Reject the null hypothesis
B) Can't reject the null hypothesis

Correct Answer

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In testing the difference between two population variances,it is a common practice to compute the F statistic so that its value is always greater than or equal to one.

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The mid-distance running coach,Zdravko Popovich,for the Olympic team of an eastern European country claims that his six-month training program significantly reduces the average time to complete a 1500-meter run.Five mid-distance runners were randomly selected before they were trained with coach Popovich's six-month training program and their completion time of 1500-meter run was recorded (in minutes) .After six months of training under coach Popovich,the same five runners' 1500 meter run time was recorded again the results are given below. The mid-distance running coach,Zdravko Popovich,for the Olympic team of an eastern European country claims that his six-month training program significantly reduces the average time to complete a 1500-meter run.Five mid-distance runners were randomly selected before they were trained with coach Popovich's six-month training program and their completion time of 1500-meter run was recorded (in minutes) .After six months of training under coach Popovich,the same five runners' 1500 meter run time was recorded again the results are given below. Construct the appropriate 95% confidence interval.(s<sub>d</sub> = .228) A) (0.063 0.497) B) (-0.206 0.766) C) (-0.003 0.563) D) (0.018 0.542) Construct the appropriate 95% confidence interval.(sd = .228)


A) (0.063 0.497)
B) (-0.206 0.766)
C) (-0.003 0.563)
D) (0.018 0.542)

Correct Answer

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When we test H0: µ1- µ2 ≤\le 0,HA: µ1- µ2> 0, When we test H<sub>0</sub>: µ<sub>1</sub>- µ<sub>2</sub> \le 0,H<sub>A</sub>: µ<sub>1</sub>- µ<sub>2</sub>> 0, <sub>1</sub> = 15.4, <sub>2</sub> = 14.5, \sigma <sub>1</sub> = 2, \sigma <sub>2</sub> = 2.28,n<sub>1</sub> = 35,n<sub>2</sub> = 18 at \alpha = .01,the test statistic used is: A) 1.42 B) 2.10 C) 2.33 D) 21.6 1 = 15.4, When we test H<sub>0</sub>: µ<sub>1</sub>- µ<sub>2</sub> \le 0,H<sub>A</sub>: µ<sub>1</sub>- µ<sub>2</sub>> 0, <sub>1</sub> = 15.4, <sub>2</sub> = 14.5, \sigma <sub>1</sub> = 2, \sigma <sub>2</sub> = 2.28,n<sub>1</sub> = 35,n<sub>2</sub> = 18 at \alpha = .01,the test statistic used is: A) 1.42 B) 2.10 C) 2.33 D) 21.6 2 = 14.5, σ\sigma 1 = 2, σ\sigma 2 = 2.28,n1 = 35,n2 = 18 at α\alpha = .01,the test statistic used is:


A) 1.42
B) 2.10
C) 2.33
D) 21.6

Correct Answer

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