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An experiment consists of tossing 4 coins successively.The number of sample points in this experiment is


A) 16
B) 8
C) 4
D) 2

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If P(A|B) = .2 and P(Bc) = .6,then P(B|A)


A) is .8
B) is .12
C) is .33
D) cannot be determined.

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A joint probability can have a value greater than 1.

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P(A|B)= P(AC|B)for all events A and B.

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P(A|B)+ P(A|BC)= 1 for all events A and B.

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Before drawing any conclusions about the relationship between two variables shown in a crosstabulation,you should


A) investigate whether any hidden variables could affect the conclusions
B) construct a scatter diagram and find the trendline
C) develop a relative frequency distribution
D) construct an ogive for each of the variables

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If A and B are mutually exclusive events,then P(A | B)= 0.

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Any process that generates well-defined outcomes is


A) an event
B) an experiment
C) a sample point
D) None of the other answers is correct.

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Discuss the problems inherent in using words such as "likely," "possibly," or "probably" to convey degree of belief.​

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Using words such as "likely," "possibly,...

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Describe four experiments and list the experimental outcomes associated with each one.​

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Experiment 1: Testing the effects of caf...

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Explain the difference between mutually exclusive and independent events.Can a pair of events be both mutually exclusive and independent?​

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Mutually exclusive events are events tha...

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A posterior probability is a conditional probability.

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When the conclusions based upon the aggregated crosstabulation can be completely reversed if we look at the unaggregated data,the occurrence is known as


A) reverse correlation
B) inferential statistics
C) Simpson's paradox
D) disaggregation

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Which of the following is not a valid representation of a probability?


A) 35%
B) 0
C) 1.04
D) 3/8

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The complement of P(A | B) is


A) P(AC | B)
B) P(A | BC)
C) P(B | A)
D) P(A I B)

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One of the basic requirements of probability is


A) for each experimental outcome Ei,we must have P(Ei) ≥ 1
B) P(A) = P(Ac) − 1
C) if there are k experimental outcomes,then P(E1) + P(E2) + ...+ P(Ek) = 1
D) both P(A) = P(Ac) − 1 and if there are k experimental outcomes,then P(E1) + P(E2) + ...+ P(Ek) = 1

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P(A|B)= P(B|A)for all events A and B.

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If P(A|B) = .4,then


A) P(B|A) = .6
B) P(A) *P(B) = .4
C) P(A) / P(B) = .4
D) None of the alternatives is correct.

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P(A|B)= 1 − P(B|A)for all events A and B.

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Two events that are mutually exclusive cannot be independent.

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