An agricultural researcher plants 25 plots with a new variety of yellow corn.Assume that the yield per acre for the new variety of yellow corn follows a Normal distribution with an unknown mean of  and a standard deviation of  = 10 bushels per acre.If the average yield for these 25 plots is  and a standard deviation of  = 10 bushels per acre.If the average yield for these 25 plots is = 150 bushels per acre,what is a 90% confidence interval for  ? A) 150 ± 0.784 B) 150 ± 2.00 C) 150 ± 3.29 D) 150 ± 3.92 class=answers-bank-image d-inline rel=preload = 150 bushels per acre,what is a 90% confidence interval for  ?A) 150 ± 0.784B) 150 ± 2.00C) 150 ± 3.29D) 150 ± 3.92

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An agricultural researcher plants 25 plots with a new variety of yellow corn.Assume that the yield per acre for the new variety of yellow corn follows a Normal distribution with an unknown mean of    and a standard deviation of    = 10 bushels per acre.If the average yield for these 25 plots is    and a standard deviation of    = 10 bushels per acre.If the average yield for these 25 plots is   = 150 bushels per acre,what is a 90% confidence interval for   ? A) 150 ± 0.784 B) 150 ± 2.00 C) 150 ± 3.29 D) 150 ± 3.92 class=answers-bank-image d-inline rel=preload > = 150 bushels per acre,what is a 90% confidence interval for   ?A) 150 ± 0.784B) 150 ± 2.00C) 150 ± 3.29D) 150 ± 3.92

jessica guillen · Accepted Answer

Final Answer : C, Explanation :  We use the formula for the confidence interval for the mean:CI = x̄ ± z* (σ/√n)where x̄ = 150 (sample mean), σ = 10 (population standard deviation), n = 25 (sample size), and z* is the critical value for a 90% confidence level, which is 1.645 (from a standard normal distribution table).Substituting the values, we get:CI = 150 ± 1.645 * (10/√25) = 150 ± 3.29Therefore, the 90% confidence interval for the population mean yield is 150 ± 3.29 bushels per acre. The closest answer choice is (C).

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