The probability that Pete will catch fish when he goes fishing is .88.Pete is going to fish 3 days next week.Define the random variable x to be the number of days Pete catches fish.The variance of the number of days Pete will catch fish is

A) 0.56.
B) 0.88.
C) 2.64.
D) 0.3168.

Question

Luis M Corona · Accepted Answer

Final Answer : D, Explanation :   The variance of a binomial distribution is given by the formula   σ 2 = n p ( 1 − p )  \sigma^2 = np(1-p)  σ 2 = n p ( 1 − p )  , where   n  n  n   is the number of trials,   p  p  p   is the probability of success on each trial. Here,   n = 3  n = 3  n = 3   (the number of days Pete goes fishing) and   p = 0.88  p = 0.88  p = 0.88   (the probability that Pete will catch fish on any given day). Thus, the variance   σ 2 = 3 ( 0.88 ) ( 1 − 0.88 ) = 3 ( 0.88 ) ( 0.12 ) = 0.3168  \sigma^2 = 3(0.88)(1-0.88) = 3(0.88)(0.12) = 0.3168  σ 2 = 3 ( 0.88 ) ( 1 − 0.88 ) = 3 ( 0.88 ) ( 0.12 ) = 0.3168  .

The probability that Pete will catch fish when he goes fishing is .88.Pete is going to fish 3 days next week.Define the random variable x to be the number of days Pete catches fish.The variance of the number of days Pete will catch fish is

A) 0.56.
B) 0.88.
C) 2.64.
D) 0.3168.

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The probability that Pete will catch fish when he goes fishing is .88.Pete is going to fish 3 days next week.Define the random variable x to be the number of days Pete catches fish.The variance of the number of days Pete will catch fish isA) 0.56.B) 0.88.C) 2.64.D) 0.3168.

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Learning Objectives

Learning Objectives

Related questions

The probability that Pete will catch fish when he goes fishing is .88.Pete is going to fish 3 days next week.Define the random variable x to be the number of days Pete catches fish.The variance of the number of days Pete will catch fish is

A) 0.56.
B) 0.88.
C) 2.64.
D) 0.3168.